Module « scipy.stats »
Signature de la fonction linregress
def linregress(x, y=None, alternative='two-sided')
Description
linregress.__doc__
Calculate a linear least-squares regression for two sets of measurements.
Parameters
----------
x, y : array_like
Two sets of measurements. Both arrays should have the same length. If
only `x` is given (and ``y=None``), then it must be a two-dimensional
array where one dimension has length 2. The two sets of measurements
are then found by splitting the array along the length-2 dimension. In
the case where ``y=None`` and `x` is a 2x2 array, ``linregress(x)`` is
equivalent to ``linregress(x[0], x[1])``.
alternative : {'two-sided', 'less', 'greater'}, optional
Defines the alternative hypothesis. Default is 'two-sided'.
The following options are available:
* 'two-sided': the slope of the regression line is nonzero
* 'less': the slope of the regression line is less than zero
* 'greater': the slope of the regression line is greater than zero
.. versionadded:: 1.7.0
Returns
-------
result : ``LinregressResult`` instance
The return value is an object with the following attributes:
slope : float
Slope of the regression line.
intercept : float
Intercept of the regression line.
rvalue : float
Correlation coefficient.
pvalue : float
The p-value for a hypothesis test whose null hypothesis is
that the slope is zero, using Wald Test with t-distribution of
the test statistic. See `alternative` above for alternative
hypotheses.
stderr : float
Standard error of the estimated slope (gradient), under the
assumption of residual normality.
intercept_stderr : float
Standard error of the estimated intercept, under the assumption
of residual normality.
See Also
--------
scipy.optimize.curve_fit :
Use non-linear least squares to fit a function to data.
scipy.optimize.leastsq :
Minimize the sum of squares of a set of equations.
Notes
-----
Missing values are considered pair-wise: if a value is missing in `x`,
the corresponding value in `y` is masked.
For compatibility with older versions of SciPy, the return value acts
like a ``namedtuple`` of length 5, with fields ``slope``, ``intercept``,
``rvalue``, ``pvalue`` and ``stderr``, so one can continue to write::
slope, intercept, r, p, se = linregress(x, y)
With that style, however, the standard error of the intercept is not
available. To have access to all the computed values, including the
standard error of the intercept, use the return value as an object
with attributes, e.g.::
result = linregress(x, y)
print(result.intercept, result.intercept_stderr)
Examples
--------
>>> import matplotlib.pyplot as plt
>>> from scipy import stats
>>> rng = np.random.default_rng()
Generate some data:
>>> x = rng.random(10)
>>> y = 1.6*x + rng.random(10)
Perform the linear regression:
>>> res = stats.linregress(x, y)
Coefficient of determination (R-squared):
>>> print(f"R-squared: {res.rvalue**2:.6f}")
R-squared: 0.717533
Plot the data along with the fitted line:
>>> plt.plot(x, y, 'o', label='original data')
>>> plt.plot(x, res.intercept + res.slope*x, 'r', label='fitted line')
>>> plt.legend()
>>> plt.show()
Calculate 95% confidence interval on slope and intercept:
>>> # Two-sided inverse Students t-distribution
>>> # p - probability, df - degrees of freedom
>>> from scipy.stats import t
>>> tinv = lambda p, df: abs(t.ppf(p/2, df))
>>> ts = tinv(0.05, len(x)-2)
>>> print(f"slope (95%): {res.slope:.6f} +/- {ts*res.stderr:.6f}")
slope (95%): 1.453392 +/- 0.743465
>>> print(f"intercept (95%): {res.intercept:.6f}"
... f" +/- {ts*res.intercept_stderr:.6f}")
intercept (95%): 0.616950 +/- 0.544475
Améliorations / Corrections
Vous avez des améliorations (ou des corrections) à proposer pour ce document : je vous remerçie par avance de m'en faire part, cela m'aide à améliorer le site.
Emplacement :
Description des améliorations :