Module « numpy.matlib »
Signature de la fonction take_along_axis
def take_along_axis(arr, indices, axis)
Description
take_along_axis.__doc__
Take values from the input array by matching 1d index and data slices.
This iterates over matching 1d slices oriented along the specified axis in
the index and data arrays, and uses the former to look up values in the
latter. These slices can be different lengths.
Functions returning an index along an axis, like `argsort` and
`argpartition`, produce suitable indices for this function.
.. versionadded:: 1.15.0
Parameters
----------
arr: ndarray (Ni..., M, Nk...)
Source array
indices: ndarray (Ni..., J, Nk...)
Indices to take along each 1d slice of `arr`. This must match the
dimension of arr, but dimensions Ni and Nj only need to broadcast
against `arr`.
axis: int
The axis to take 1d slices along. If axis is None, the input array is
treated as if it had first been flattened to 1d, for consistency with
`sort` and `argsort`.
Returns
-------
out: ndarray (Ni..., J, Nk...)
The indexed result.
Notes
-----
This is equivalent to (but faster than) the following use of `ndindex` and
`s_`, which sets each of ``ii`` and ``kk`` to a tuple of indices::
Ni, M, Nk = a.shape[:axis], a.shape[axis], a.shape[axis+1:]
J = indices.shape[axis] # Need not equal M
out = np.empty(Ni + (J,) + Nk)
for ii in ndindex(Ni):
for kk in ndindex(Nk):
a_1d = a [ii + s_[:,] + kk]
indices_1d = indices[ii + s_[:,] + kk]
out_1d = out [ii + s_[:,] + kk]
for j in range(J):
out_1d[j] = a_1d[indices_1d[j]]
Equivalently, eliminating the inner loop, the last two lines would be::
out_1d[:] = a_1d[indices_1d]
See Also
--------
take : Take along an axis, using the same indices for every 1d slice
put_along_axis :
Put values into the destination array by matching 1d index and data slices
Examples
--------
For this sample array
>>> a = np.array([[10, 30, 20], [60, 40, 50]])
We can sort either by using sort directly, or argsort and this function
>>> np.sort(a, axis=1)
array([[10, 20, 30],
[40, 50, 60]])
>>> ai = np.argsort(a, axis=1); ai
array([[0, 2, 1],
[1, 2, 0]])
>>> np.take_along_axis(a, ai, axis=1)
array([[10, 20, 30],
[40, 50, 60]])
The same works for max and min, if you expand the dimensions:
>>> np.expand_dims(np.max(a, axis=1), axis=1)
array([[30],
[60]])
>>> ai = np.expand_dims(np.argmax(a, axis=1), axis=1)
>>> ai
array([[1],
[0]])
>>> np.take_along_axis(a, ai, axis=1)
array([[30],
[60]])
If we want to get the max and min at the same time, we can stack the
indices first
>>> ai_min = np.expand_dims(np.argmin(a, axis=1), axis=1)
>>> ai_max = np.expand_dims(np.argmax(a, axis=1), axis=1)
>>> ai = np.concatenate([ai_min, ai_max], axis=1)
>>> ai
array([[0, 1],
[1, 0]])
>>> np.take_along_axis(a, ai, axis=1)
array([[10, 30],
[40, 60]])
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