Module « numpy.matlib »
Signature de la fonction expand_dims
def expand_dims(a, axis)
Description
expand_dims.__doc__
Expand the shape of an array.
Insert a new axis that will appear at the `axis` position in the expanded
array shape.
Parameters
----------
a : array_like
Input array.
axis : int or tuple of ints
Position in the expanded axes where the new axis (or axes) is placed.
.. deprecated:: 1.13.0
Passing an axis where ``axis > a.ndim`` will be treated as
``axis == a.ndim``, and passing ``axis < -a.ndim - 1`` will
be treated as ``axis == 0``. This behavior is deprecated.
.. versionchanged:: 1.18.0
A tuple of axes is now supported. Out of range axes as
described above are now forbidden and raise an `AxisError`.
Returns
-------
result : ndarray
View of `a` with the number of dimensions increased.
See Also
--------
squeeze : The inverse operation, removing singleton dimensions
reshape : Insert, remove, and combine dimensions, and resize existing ones
doc.indexing, atleast_1d, atleast_2d, atleast_3d
Examples
--------
>>> x = np.array([1, 2])
>>> x.shape
(2,)
The following is equivalent to ``x[np.newaxis, :]`` or ``x[np.newaxis]``:
>>> y = np.expand_dims(x, axis=0)
>>> y
array([[1, 2]])
>>> y.shape
(1, 2)
The following is equivalent to ``x[:, np.newaxis]``:
>>> y = np.expand_dims(x, axis=1)
>>> y
array([[1],
[2]])
>>> y.shape
(2, 1)
``axis`` may also be a tuple:
>>> y = np.expand_dims(x, axis=(0, 1))
>>> y
array([[[1, 2]]])
>>> y = np.expand_dims(x, axis=(2, 0))
>>> y
array([[[1],
[2]]])
Note that some examples may use ``None`` instead of ``np.newaxis``. These
are the same objects:
>>> np.newaxis is None
True
Améliorations / Corrections
Vous avez des améliorations (ou des corrections) à proposer pour ce document : je vous remerçie par avance de m'en faire part, cela m'aide à améliorer le site.
Emplacement :
Description des améliorations :