Module « scipy.ndimage »
Signature de la fonction distance_transform_edt
def distance_transform_edt(input, sampling=None, return_distances=True, return_indices=False, distances=None, indices=None)
Description
distance_transform_edt.__doc__
Exact Euclidean distance transform.
In addition to the distance transform, the feature transform can
be calculated. In this case the index of the closest background
element to each foreground element is returned in a separate array.
Parameters
----------
input : array_like
Input data to transform. Can be any type but will be converted
into binary: 1 wherever input equates to True, 0 elsewhere.
sampling : float, or sequence of float, optional
Spacing of elements along each dimension. If a sequence, must be of
length equal to the input rank; if a single number, this is used for
all axes. If not specified, a grid spacing of unity is implied.
return_distances : bool, optional
Whether to calculate the distance transform.
Default is True.
return_indices : bool, optional
Whether to calculate the feature transform.
Default is False.
distances : float64 ndarray, optional
An output array to store the calculated distance transform, instead of
returning it.
`return_distances` must be True.
It must be the same shape as `input`.
indices : int32 ndarray, optional
An output array to store the calculated feature transform, instead of
returning it.
`return_indicies` must be True.
Its shape must be `(input.ndim,) + input.shape`.
Returns
-------
distances : float64 ndarray, optional
The calculated distance transform. Returned only when
`return_distances` is True and `distances` is not supplied.
It will have the same shape as the input array.
indices : int32 ndarray, optional
The calculated feature transform. It has an input-shaped array for each
dimension of the input. See example below.
Returned only when `return_indices` is True and `indices` is not
supplied.
Notes
-----
The Euclidean distance transform gives values of the Euclidean
distance::
n
y_i = sqrt(sum (x[i]-b[i])**2)
i
where b[i] is the background point (value 0) with the smallest
Euclidean distance to input points x[i], and n is the
number of dimensions.
Examples
--------
>>> from scipy import ndimage
>>> a = np.array(([0,1,1,1,1],
... [0,0,1,1,1],
... [0,1,1,1,1],
... [0,1,1,1,0],
... [0,1,1,0,0]))
>>> ndimage.distance_transform_edt(a)
array([[ 0. , 1. , 1.4142, 2.2361, 3. ],
[ 0. , 0. , 1. , 2. , 2. ],
[ 0. , 1. , 1.4142, 1.4142, 1. ],
[ 0. , 1. , 1.4142, 1. , 0. ],
[ 0. , 1. , 1. , 0. , 0. ]])
With a sampling of 2 units along x, 1 along y:
>>> ndimage.distance_transform_edt(a, sampling=[2,1])
array([[ 0. , 1. , 2. , 2.8284, 3.6056],
[ 0. , 0. , 1. , 2. , 3. ],
[ 0. , 1. , 2. , 2.2361, 2. ],
[ 0. , 1. , 2. , 1. , 0. ],
[ 0. , 1. , 1. , 0. , 0. ]])
Asking for indices as well:
>>> edt, inds = ndimage.distance_transform_edt(a, return_indices=True)
>>> inds
array([[[0, 0, 1, 1, 3],
[1, 1, 1, 1, 3],
[2, 2, 1, 3, 3],
[3, 3, 4, 4, 3],
[4, 4, 4, 4, 4]],
[[0, 0, 1, 1, 4],
[0, 1, 1, 1, 4],
[0, 0, 1, 4, 4],
[0, 0, 3, 3, 4],
[0, 0, 3, 3, 4]]])
With arrays provided for inplace outputs:
>>> indices = np.zeros(((np.ndim(a),) + a.shape), dtype=np.int32)
>>> ndimage.distance_transform_edt(a, return_indices=True, indices=indices)
array([[ 0. , 1. , 1.4142, 2.2361, 3. ],
[ 0. , 0. , 1. , 2. , 2. ],
[ 0. , 1. , 1.4142, 1.4142, 1. ],
[ 0. , 1. , 1.4142, 1. , 0. ],
[ 0. , 1. , 1. , 0. , 0. ]])
>>> indices
array([[[0, 0, 1, 1, 3],
[1, 1, 1, 1, 3],
[2, 2, 1, 3, 3],
[3, 3, 4, 4, 3],
[4, 4, 4, 4, 4]],
[[0, 0, 1, 1, 4],
[0, 1, 1, 1, 4],
[0, 0, 1, 4, 4],
[0, 0, 3, 3, 4],
[0, 0, 3, 3, 4]]])
Améliorations / Corrections
Vous avez des améliorations (ou des corrections) à proposer pour ce document : je vous remerçie par avance de m'en faire part, cela m'aide à améliorer le site.
Emplacement :
Description des améliorations :