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Return whether the area enclosed by the path contains the given points.
The path is always treated as closed; i.e. if the last code is not
CLOSEPOLY an implicit segment connecting the last vertex to the first
vertex is assumed.
Parameters
----------
points : (N, 2) array
The points to check. Columns contain x and y values.
transform : `matplotlib.transforms.Transform`, optional
If not ``None``, *points* will be compared to ``self`` transformed
by *transform*; i.e. for a correct check, *transform* should
transform the path into the coordinate system of *points*.
radius : float, default: 0
Add an additional margin on the path in coordinates of *points*.
The path is extended tangentially by *radius/2*; i.e. if you would
draw the path with a linewidth of *radius*, all points on the line
would still be considered to be contained in the area. Conversely,
negative values shrink the area: Points on the imaginary line
will be considered outside the area.
Returns
-------
length-N bool array
Notes
-----
The current algorithm has some limitations:
- The result is undefined for points exactly at the boundary
(i.e. at the path shifted by *radius/2*).
- The result is undefined if there is no enclosed area, i.e. all
vertices are on a straight line.
- If bounding lines start to cross each other due to *radius* shift,
the result is not guaranteed to be correct.
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